Java: Check if a specified array of integers contains 10 or 30

Last update on May 12 2025 13:12:42 (UTC/GMT +8 hours)

Contains 10 or 30

Write a Java program to check if a specified array of integers contains 10 or 30.

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.*;

public class Exercise102 {
    public static void main(String[] args) {
        int[] array_nums = {11, 11, 13, 31, 45, 20, 33, 53};
        int result = 1; 
        System.out.println("Original Array: "+Arrays.toString(array_nums));

        // Iterate through the array
        for(int i = 0; i < array_nums.length; i++) {
            if(array_nums[i] == 10 || array_nums[i] == 30) {
                // If the element is equal to 10 or 30, set the result to 0
                result = 0;
            }
        }

        if (result == 1)
            System.out.printf(String.valueOf(false)); // If the result is 1, print false
        else
            System.out.printf(String.valueOf(true)); // If the result is not 1, print true
    }
}

Sample Output:

Original Array: [11, 11, 13, 31, 45, 20, 33, 53]                       
false 

Flowchart:

For more Practice: Solve these Related Problems:

• Modify the program to check if the array contains both 10 and 30.
• Write a program to check if the array contains at least one even number.
• Modify the program to return the index of 10 or 30 if found.
• Write a program to count occurrences of 10 and 30.

Go to:

• Java Basic Programming Exercises Home ↩
• Java Exercises Home ↩

PREV : Check 10 Exceeds 20 in Array.
NEXT : Array After Last 10

Java Code Editor: