Java: Get the majority element from a given array of integers containing duplicates
Java Array: Exercise-38 with Solution
Write a Java program to get the majority element from an array of integers containing duplicates.
Majority element: A majority element is an element that appears more than n/2 times where n is the array size.
Pictorial Presentation:
Sample Solution:
Java Code:
// Import necessary Java libraries.
import java.util.HashMap;
import java.util.Map;
import java.util.Iterator;
import java.util.Arrays;
// Define a class named Main.
public class Main
{
// The main method for executing the program.
public static void main (String[] args)
{
// Define an array to test for the majority element.
int nums[] = { 1, 6, 6, 5, 7, 4, 1, 7, 7, 7, 7, 7, 7, 7, 2 };
System.out.println("Original Array : " + Arrays.toString(nums));
// Call the MajorityElement method to find the majority element.
int result = MajorityElement(nums);
if (result != -1)
System.out.println("Majority element is " + result);
else
System.out.println("Majority element does not exist");
}
// A method to find the majority element in an array.
public static int MajorityElement(int arra1[])
{
int n = arra1.length;
// Create a hash map to store element frequencies.
Map<Integer, Integer> map = new HashMap<Integer, Integer>();
// Calculate the frequency of each element in the map.
for (int i = 0; i < n; i++)
{
if (map.get(arra1[i]) == null)
map.put(arra1[i], 0);
map.put(arra1[i], map.get(arra1[i]) + 1);
}
// Return the element if its count is more than n/2.
Iterator it = map.entrySet().iterator();
while (it.hasNext())
{
Map.Entry pair = (Map.Entry)it.next();
if ((int)pair.getValue() > n/2)
return (int)pair.getKey();
it.remove();
}
// No majority element found.
return -1;
}
}
Sample Output:
Original Array : [1, 6, 6, 5, 7, 4, 1, 7, 7, 7, 7, 7, 7, 7, 2] Majority element is 7
Flowchart:
Java Code Editor:
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