C#: Determine the LCM of two numbers using HCF

using System;  // Importing necessary namespace

public class Exercise44  // Declaration of the Exercise44 class
{  
    public static void Main()  // Main method, entry point of the program
    {  
        // Declaration of variables
        int i, n1, n2, j, hcf = 1, lcm;  

        // Displaying information about determining the LCM of two numbers using HCF
        Console.Write("\n\n");
        Console.Write("Determine the LCM of two numbers using HCF:\n");
        Console.Write("---------------------------------------------");
        Console.Write("\n\n");	

        // Prompting user to input the first number for LCM
        Console.Write("Input 1st number for LCM: ");  
        n1 = Convert.ToInt32(Console.ReadLine());	

        // Prompting user to input the second number for LCM
        Console.Write("Input 2nd number for LCM: ");  
        n2 = Convert.ToInt32(Console.ReadLine());	

        j = (n1 < n2) ? n1 : n2;  // Determining the smaller number between n1 and n2

        // Loop to find the Highest Common Factor (HCF) of n1 and n2
        for (i = 1; i <= j; i++)  
        {  
            if (n1 % i == 0 && n2 % i == 0)  
            {  
                hcf = i;  // Updating the HCF whenever both numbers are divisible by 'i'
            }  
        }  

        // Calculating the LCM using the formula: (n1 * n2) / HCF
        lcm = (n1 * n2) / hcf;

        // Displaying the calculated LCM of the given numbers
        Console.Write("\nThe LCM of {0} and {1} is : {2}\n\n", n1, n2, lcm);  
    }
}