C#: Find the number and sum of all integer between 100 and 200, divisible by 9
Write a C# Sharp program to find the number and sum of all integers between 100 and 200 divisible by 9.
Visual Presentation:

Sample Solution:
C# Sharp Code:
using System; // Importing necessary namespace
public class Exercise39 // Declaration of the Exercise39 class
{
public static void Main() // Main method, entry point of the program
{
int i, sum = 0; // Declaration of variables: 'i' for looping, 'sum' for storing the sum
Console.Write("\n\n"); // Displaying new lines
Console.Write("Find the number and sum of all integers between 100 and 200, divisible by 9:\n"); // Displaying the purpose of the program
Console.Write("-----------------------------------------------------------------------------\n\n"); // Displaying a separator and new lines
Console.Write("Numbers between 100 and 200, divisible by 9 : \n"); // Displaying the range of numbers
for (i = 101; i < 200; i++) // Loop through the range from 101 to 199
{
if (i % 9 == 0) // Checking if the number is divisible by 9
{
Console.Write("{0} ", i); // Displaying the number divisible by 9
sum += i; // Adding the number to the 'sum' variable
}
}
Console.Write("\n\nThe sum : {0} \n", sum); // Displaying the total sum of numbers divisible by 9
}
}
Sample Output:
Find the number and sum of all integer between 100 and 200, divisible by 9: ----------------------------------------------------------------------------- Numbers between 100 and 200, divisible by 9 : 108 117 126 135 144 153 162 171 180 189 198 The sum : 1683
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C# Sharp Code Editor:
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