C#: Count positive and negative numbers in a given array of integers

Last update on December 20 2024 12:37:42 (UTC/GMT +8 hours)

Count Positives and Negatives in Array

Write a C# Sharp program to count positive and negative numbers in a given array of integers.

Sample Solution:

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {
            // Array declaration and initialization with integer elements
            int[] nums = { 10, -11, 12, -13, 14, -18, 19, -20 };

            // Displaying the original elements of the array 'nums'
            Console.WriteLine("Original Array elements:");
            foreach (var item in nums)
            {
                Console.Write(item.ToString() + " ");
            }

            // Calling the 'test' method and displaying the count of positive and negative numbers in the array 'nums'
            Console.WriteLine(test(nums));

            // Another array declaration and initialization with integer elements
            int[] nums1 = { -4, -3, -2, 0, 3, 5, 6, 2, 6 };

            // Displaying the original elements of the array 'nums1'
            Console.WriteLine("\nOriginal Array elements:");
            foreach (var item in nums1)
            {
                Console.Write(item.ToString() + " ");
            }

            // Calling the 'test' method and displaying the count of positive and negative numbers in the array 'nums1'
            Console.WriteLine(test(nums1));

            // Empty array declaration (no elements)
            int[] nums2 = {};

            // Displaying the original elements of the array 'nums2' (empty array)
            Console.WriteLine("\nOriginal Array elements:");
            foreach (var item in nums2)
            {
                Console.Write(item.ToString() + " ");
            }

            // Calling the 'test' method for the empty array 'nums2' and displaying the count of positive and negative numbers
            Console.WriteLine(test(nums2));
        }

        // Method to count the number of positive and negative numbers in an integer array
        public static string test(int[] nums)
        {
            // Filtering positive and negative numbers using LINQ 'Where' clause
            var pos = nums.Where(n => n > 0);
            var neg = nums.Where(n => n < 0);

            // Returning the count of positive and negative numbers as a formatted string
            return "\nNumber of positive numbers: " + pos.Count() + "\nNumber of negative numbers: " + neg.Count();
        }
    }
}

Sample Output:

Original Array elements:
10 -11 12 -13 14 -18 19 -20 
Number of positive numbers: 4
Number of negative numbers: 4

Original Array elements:
-4 -3 -2 0 3 5 6 2 6 
Number of positive numbers: 5
Number of negative numbers: 3

Original Array elements:

Number of positive numbers: 0
Number of negative numbers: 0

Flowchart:

C# Sharp Code Editor:

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