C#: Check two given integers and return the value whichever value is nearest to 13 without going over

Last update on June 26 2025 13:04:59 (UTC/GMT +8 hours)

Nearest to 13 Without Crossing

Write a C# Sharp program to check two integers and return the value nearest to 13 without crossing over. Return 0 if both numbers exceed.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Import the System namespace which contains fundamental types and base classes
using System.Collections.Generic; // Import the System.Collections.Generic namespace for collections
using System.Linq; // Import the LINQ namespace for LINQ functionality
using System.Text; // Import the System.Text namespace for string manipulation
using System.Threading.Tasks; // Import the System.Threading.Tasks namespace for asynchronous operations

namespace exercises // Define a namespace called 'exercises'
{
    class Program // Define a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Output the result of test function with different pairs of integers as arguments
            Console.WriteLine(test(4, 5)); // Test with integers 4 and 5
            Console.WriteLine(test(7, 12)); // Test with integers 7 and 12
            Console.WriteLine(test(10, 13)); // Test with integers 10 and 13
            Console.WriteLine(test(17, 33)); // Test with integers 17 and 33
            Console.ReadLine(); // Wait for user input before closing the console window
        }

        // Function definition of test function that takes two integers 'x' and 'y' and returns an integer
        public static int test(int x, int y)
        {
            // Conditional checks based on the values of 'x' and 'y' to determine the returned result
            if (x > 13 && y > 13) // If both 'x' and 'y' are greater than 13, return 0
                return 0;
            if (x <= 13 && y > 13) // If 'x' is less than or equal to 13 and 'y' is greater than 13, return 'x'
                return x;
            if (y <= 13 && x > 13) // If 'y' is less than or equal to 13 and 'x' is greater than 13, return 'y'
                return y;
            return x > y ? x : y; // If none of the above conditions are met, return the greater of 'x' and 'y'
        }
    }
}

Sample Output:

5
12
13
0

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C# program to return the closest number to 13 from a list of three, without exceeding 13.
• Write a C# program to return the maximum number less than or equal to 13 from two given integers.
• Write a C# program to check which number is closer to 13 but not equal, and return the difference.
• Write a C# program to return the closer number to 13 unless both are greater, then return -1.

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