C#: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x

C# Sharp Basic Algorithm: Exercise-54 with Solution

Write a C# Sharp program to compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x. If the sum has more digits than x return x without y.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Import the System namespace which contains fundamental types and base classes
using System.Linq; // Import the LINQ namespace for LINQ functionality

namespace exercises // Define a namespace called 'exercises'
{
    class Program // Define a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Output the result of test function with different integer arguments
            Console.WriteLine(test(4, 5)); // Test with integers 4 and 5
            Console.WriteLine(test(7, 4)); // Test with integers 7 and 4
            Console.WriteLine(test(10, 10)); // Test with integers 10 and 10
            Console.ReadLine(); // Wait for user input before closing the console window
        }

        // Function definition of test function that takes two integers 'x' and 'y' and returns an integer
        public static int test(int x, int y)
        {
            // Check if the length of the sum of 'x' and 'y' converted to a string is greater than the length of 'x' converted to a string
            // If true, return 'x'; otherwise, return the sum of 'x' and 'y'
            return (x + y).ToString().Length > x.ToString().Length ? x : x + y;
        }
    }
}

Sample Output:

9
7
20

Flowchart:

C# Sharp Code Editor:

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