C#: Create a new list of the rightmost digits from a given list of positive integers

Last update on December 20 2024 12:38:16 (UTC/GMT +8 hours)

Rightmost Digits of Integers

Write a C# Sharp program to create a list of the rightmost digits from a given list of positive integers.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System; // Importing the System namespace for basic functionality
using System.Collections.Generic; // Importing the namespace for working with collections
using System.Linq; // Importing the namespace for LINQ operations

namespace exercises // Defining a namespace called 'exercises'
{
   class Program // Defining a class named 'Program'
   {
       static void Main(string[] args) // The entry point of the program
       {            
           // Calling the 'test' method with a new list of integers as input
           List<int> mylist = test(new List<int>(new int[] { 10, 22, 35 , 41 }));

           // Displaying elements of 'mylist' in the console
           foreach(var i in mylist)
           {
               Console.Write(i.ToString()+" "); // Output each element followed by a space
           }     
       }                  

       // Method that takes a List of integers and extracts the last digit of each number
       public static List<int> test(List<int> nums)
       {
           // Using LINQ to extract the last digit of each number in the 'nums' list
           IEnumerable<int> digits = nums.Select(x => x % 10);

           // Converting the IEnumerable 'digits' to a new List and returning it
           return digits.ToList();
       }    
   } 
}

Sample Output:

0 2 5 1

Flowchart:

C# Sharp Code Editor:

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