C#: Create a new list from a given list of integers where each integer multiplied by itself three times

Last update on December 20 2024 12:38:14 (UTC/GMT +8 hours)

Cube Each Integer

Write a C# Sharp program to create a list from a given list of integers. Each integer is multiplied by itself three times.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System; // Importing the System namespace for basic functionality
using System.Collections.Generic; // Importing the namespace for working with collections
using System.Linq; // Importing the namespace for LINQ operations

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Creating a List of integers and assigning the result of 'test' method
            List<int> mylist = test(new List<int>(new int[] { 1, 2, 3 , 4 }));

            // Displaying the elements of 'mylist' in the console
            foreach (var i in mylist)
            {
                Console.Write(i.ToString() + " "); // Output each element followed by a space
            }
        }

        // Method that takes a List of integers and returns a new List with each element cubed
        public static List<int> test(List<int> nums)
        {
            // Using LINQ to cube each element of 'nums' and store it in 'squared'
            IEnumerable<int> squared = nums.Select(x => x * x * x);

            // Converting the IEnumerable 'squared' to a new List and returning it
            return squared.ToList();
        }
    }
}

Sample Output:

1 8 27 64

Flowchart:

C# Sharp Code Editor:

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