C#: Create a new array of given length using the odd numbers from a given array of positive integers

C# Sharp Basic Algorithm: Exercise-140 with Solution

Write a C# Sharp program to create an array of given length using odd numbers from a given array of positive integers.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System; // Importing the System namespace for basic functionality

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Calling the 'test' method with an array and a count value
            int[] item = test(new[] { 1, 2, 3, 5, 7, 9, 10 }, 3);

            // Displaying the new array elements in the console
            Console.Write("New array: ");
            foreach (var i in item)
            {
                Console.Write(i.ToString() + " "); // Output each element followed by a space
            }
        }

        // Method that returns an array of specified count of odd numbers from the input array
        public static int[] test(int[] nums, int count)
        {
            int[] odds = new int[count]; // Initializing a new array to store odd numbers
            int j = 0; // Initializing a counter for the 'odds' array

            // Loop through the 'nums' array to find and store 'count' number of odd numbers
            for (int i = 0; j < count; i++)
            {
                // Check if the number at 'i' index in 'nums' array is odd
                if (nums[i] % 2 != 0)
                {
                    odds[j] = nums[i]; // Store the odd number in the 'odds' array
                    j++; // Increment the counter to track the number of odd elements found
                }
            }
            return odds; // Return the array containing 'count' number of odd numbers
        }
    }
}

Sample Output:

New array: 1 3 5

Flowchart:

C# Sharp Code Editor:

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