C#: Create new array from a given array of integers shifting all even numbers before all odd numbers

Last update on December 20 2024 12:38:09 (UTC/GMT +8 hours)

Shift Even Numbers Before Odd Numbers

Write a C# Sharp program to create an array from a given array of integers. Shift all even numbers before all odd numbers.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
   class Program // Defining a class named 'Program'
   {
      static void Main(string[] args) // The entry point of the program
      {               
         // Calling the 'test' method with a given integer array 
         // and storing the modified array in 'item'
         int[] item = test(new[] { 1, 2, 5, 3, 5, 4, 6, 9, 11 }); 

         // Outputting the elements of the modified array
         Console.Write("New array: "); 
         foreach (var i in item) // Looping through each element in the 'item' array
         {
            Console.Write(i.ToString()+" "); // Outputting each element followed by a space
         }     
      }               

      // Method to rearrange the array such that even elements come before odd elements
      static int[] test(int[] numbers)
      {
         int index = 0; // Initializing an index variable to track even numbers' positions

         for (int i = 0; i < numbers.Length; i++) // Looping through the input array
         {
            if (numbers[i] % 2 == 0) // Checking if the current element is even
            {
               int temp = numbers[index]; // Swapping even and odd elements using a temp variable
               numbers[index] = numbers[i];
               numbers[i] = temp;

               index++; // Incrementing the index to track the next even number position
            }
         }
         return numbers; // Returning the modified array
      }    
   } 
}

Sample Output:

New array: 2 4 6 3 5 1 5 9 11

Flowchart:

C# Sharp Code Editor:

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