C#: Create a new array of length 3 from a given array using the elements from the middle of the array

Last update on December 20 2024 12:47:02 (UTC/GMT +8 hours)

Middle Elements in New Array of Length 3

Write a C# Sharp program to create an array length 3 from a given array (length at least 3) using the elements in the middle of the array.

visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {          
            // Calling the 'test' method with an integer array as an argument and assigning the result to the 'item' array
            int[] item = test(new[] { 1, 5, 7, 9, 11, 13 }); 

            // Outputting text to indicate the start of displaying the new array
            Console.Write("New array: ");         

            // Looping through each element of the 'item' array and displaying them
            foreach(var i in item)
            {
               Console.Write(i.ToString()+" "); // Displaying each element of the 'item' array separated by a space
            }               
        }        

        // Method to create a new array containing three elements from the middle of the input array
        static int[] test(int[] numbers)
        {
            // Calculating the middle index and selecting three elements from the input array centered around the middle
            return new int[] { numbers[numbers.Length / 2 - 1], numbers[numbers.Length / 2], numbers[numbers.Length / 2 + 1] };
        } 
    }
}

Sample Output:

New array: 7 9 11

Flowchart:

C# Sharp Code Editor:

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