C#: Remove all duplicate elements from a given array

Last update on December 20 2024 12:36:45 (UTC/GMT +8 hours)

Write a C# Sharp program that removes all duplicate elements from a given array and returns an updated array.

Sample Solution:-

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {
            // Create an array of objects containing various data types
            object[] mixedArray = new object[8];
            mixedArray[0] = 25;
            mixedArray[1] = "Anna";
            mixedArray[2] = false;
            mixedArray[3] = 25;
            mixedArray[4] = System.DateTime.Now;
            mixedArray[5] = 112.22;
            mixedArray[6] = "Anna";
            mixedArray[7] = false;

            // Display the original elements in the mixed array
            Console.WriteLine("Original array elements:");
            for (int i = 0; i < mixedArray.Length; i++)
            {
                Console.WriteLine(mixedArray[i]);
            }

            // Call the 'test' method to remove duplicates from the mixed array
            object[] result = test(mixedArray);

            // Display the elements after removing duplicates from the array
            Console.WriteLine("\nAfter removing duplicate elements from the said array:");
            for (int i = 0; i < result.Length; i++)
            {
                Console.WriteLine(result[i]);
            }
        }

        // Method to remove duplicate elements from an array of objects
        public static object[] test(object[] mixedArray)
        {
            // Use LINQ's 'Distinct' method to filter out duplicate elements and convert the result back to an array
            return mixedArray.Distinct().ToArray();
        }
    }
}

Sample Output:

Original array elements:
25
Anna
False
25
4/15/2021 12:10:51 PM
112.22
Anna
False

After removing duplicate elements from the said array:
25
Anna
False
4/15/2021 12:10:51 PM
112.22

Flowchart:

C# Sharp Code Editor:

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