C++ Exercises: Check whether a given number is Perfect or not

Last update on December 20 2024 12:24:36 (UTC/GMT +8 hours)

Write a program in C++ to check whether a given number is Perfect or not.

Visual Presentation:

Sample Solution:

C++ Code :

# include <iostream> // Include necessary libraries
# include <string>

using namespace std;

int main()
{
    int i = 1, u = 1, sum = 0, n; // Initialize variables i, u, sum, and n
    cout << "\n\n Check whether a given number is a Perfect number:\n"; // Display message for user
    cout << "------------------------------------------------------\n";

    cout << "Input a number: "; // Ask user for input
    cin >> n; // Get user input and store it in variable n

    while (u <= n) // Loop through numbers from 1 to n
    {
        if (u < n) // Check if u is less than n
        {
            if (n % u == 0) // Check if u is a divisor of n
                sum = sum + u; // Add u to the sum if it's a divisor of n
        }
        u++; // Increment u by 1 in each iteration
    }

    if (sum == n) // Check if the sum of divisors is equal to the number itself
    {
        cout << n << " is a Perfect number." << "\n"; // If the sum is equal to the number, it's a Perfect number
    }
    else
    {
        cout << n << " is not a Perfect number." << "\n"; // If the sum is not equal to the number, it's not a Perfect number
    }
}

Sample Output:

 Check whether a given number is a Perfect number:                                                   
------------------------------------------------------                                               
Input a number: 28                                                                                   
28 is a Perfect number.

Flowchart:

C++ Code Editor:

Click to Open Editor

Contribute your code and comments through Disqus.

Previous: Write a program in C++ to find the Abundant numbers (integers) between 1 to 1000.
Next: Write a program in C++ to find Perfect numbers and number of Perfect numbers between 1 to 1000.