C++ Exercises: Find Narcissistic decimal numbers within a specific range

Last update on December 20 2024 12:30:55 (UTC/GMT +8 hours)

Write a C++ program to find Narcissistic decimal numbers within a specific range.

Sample Solution:

C++ Code :

#include <iostream> // Include input-output stream library
#include <cmath> // Include math library for mathematical operations
using namespace std; // Using standard namespace

int main() // Main function
{
    int nl, nu; // Declare variables to store lower and upper limits
    cout << "\n\n Find the Narcissistic decimal numbers between a specific range: \n"; // Display purpose
    cout << " --------------------------------------------------------------------\n"; // Display purpose
    cout << " Input the lower limit: "; // Prompt user for input
    cin >> nl; // Input the lower limit
    cout << " Input the upper limit: "; // Prompt user for input
    cin >> nu; // Input the upper limit
    cout << " The Narcissistic decimal numbers between " << nl << " and " << nu << " are: \n"; // Display purpose

    int i, ctr, j, orn, n, m, sum; // Declare variables used in the following loops
    for (orn = nl; orn <= nu; orn++) // Loop through the numbers within the range [nl, nu]
    {
        ctr = 0; // Initialize the counter to zero
        sum = 0; // Initialize the sum to zero
        n = orn; // Assign the current number 'orn' to 'n'
        while (n > 0) // Loop to count the number of digits in 'n'
        {
            n = n / 10; // Divide 'n' by 10 to move to the next digit
            ctr++; // Increment the digit counter
        }
        n = orn; // Assign the current number 'orn' to 'n' again for further processing
        while (n > 0) // Loop to calculate the sum of digits raised to the power of the digit count
        {
            m = n % 10; // Extract the last digit of 'n'
            sum = sum + pow(m, ctr); // Add the current digit raised to the power of the digit count to 'sum'
            n = n / 10; // Move to the next digit by dividing 'n' by 10
        }
        if (sum == orn) // Check if the sum of digits raised to the power of the count is equal to the original number
        {
            cout << " " << orn << " "; // If equal, print the narcissistic number
        }
    }
    cout << endl; // Move to the next line
}

Sample Output:

Find the Narcissistic decimal numbers between a specific range:       
 --------------------------------------------------------------------  
 Input the lower limit: 25                                             
 Input a upper limit: 200                                              
 The Narcissistic decimal numbers between 25 and 200 are:              
 153

Flowchart:

C++ Code Editor:

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