C++ Exercises: Find Disarium numbers between 1 to 1000
Write a C++ program to find Disarium numbers between 1 and 1000.
Visual Presentation:
Sample Solution:
C++ Code :
#include<bits/stdc++.h> // Include necessary libraries
using namespace std; // Use the standard namespace
// Function to count the number of digits in a number
int DigiCount(int n)
{
int ctr_digi = 0; // Counter for digits initialized to 0
int tmpx = n; // Temporary variable to store the number
// Loop to count the digits by dividing the number by 10 until it becomes zero
while (tmpx)
{
tmpx = tmpx / 10; // Divide the number by 10
ctr_digi++; // Increment digit counter
}
return ctr_digi; // Return the count of digits in the number
}
// Function to check if a number is a Disarium Number
bool chkDisarum(int n)
{
int ctr_digi = DigiCount(n); // Calculate the count of digits in the number
int s = 0; // Initialize sum of powered digits to 0
int x = n; // Temporary variable to store the number
int pr; // Variable to store digits extracted from the number
// Loop to calculate the sum of powered digits
while (x)
{
pr = x % 10; // Extract the last digit of the number
s = s + pow(pr, ctr_digi--); // Add the powered digit to the sum
x = x / 10; // Remove the last digit from the number
}
return (s == n); // Return true if the sum of powered digits is equal to the original number
}
// Main function
int main()
{
int i; // Loop variable
cout << "\n\n Find Disarium Numbers between 1 to 1000: \n"; // Display message about the program
cout << " ---------------------------------------------\n";
cout << " The Disarium numbers are: "<<endl; // Display header for Disarium numbers
// Loop through numbers from 1 to 1000 to find and display Disarium numbers
for(i = 1; i <= 1000; i++)
{
if (chkDisarum(i)) // Check if the number is a Disarium number
cout << i << " "; // Display Disarium number if found
}
cout << endl; // Print newline after displaying all Disarium numbers
return 0; // Return 0 to indicate successful execution
}
Sample Output:
Find Disarium Numbers between 1 to 1000: --------------------------------------------- The Disarium numbers are: 1 2 3 4 5 6 7 8 9 89 135 175 518 598
Flowchart:
C++ Code Editor:
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