C++ Exercises: Check whether a number is Disarium or not

Last update on December 20 2024 12:24:24 (UTC/GMT +8 hours)

Write a C++ program to check whether a number is Disarium or not.

Visual Presentation:

C++ Exercises: Check whether a number is Disarium or not

Sample Solution:

C++ Code :

#include<bits/stdc++.h> // Include necessary libraries
using namespace std; // Use the standard namespace

// Function to count the number of digits in a number
int DigiCount(int n)
{
    int ctr_digi = 0; // Counter for digits initialized to 0
    int tmpx = n; // Temporary variable to store the number

    // Loop to count the digits by dividing the number by 10 until it becomes zero
    while (tmpx)
    {
        tmpx = tmpx / 10; // Divide the number by 10
        ctr_digi++; // Increment digit counter
    }
    return ctr_digi; // Return the count of digits in the number
}

// Function to check if a number is a Disarium Number
bool chkDisarum(int n)
{
    int ctr_digi = DigiCount(n); // Calculate the count of digits in the number
    int s = 0; // Initialize sum of powered digits to 0
    int x = n; // Temporary variable to store the number
    int pr; // Variable to store digits extracted from the number

    // Loop to calculate the sum of powered digits
    while (x)
    {
        pr = x % 10; // Extract the last digit of the number
        s = s + pow(pr, ctr_digi--); // Add the powered digit to the sum
        x = x / 10; // Remove the last digit from the number
    }
    return (s == n); // Return true if the sum of powered digits is equal to the original number
}

// Main function
int main()
{
    int dino; // Variable to store user input

    cout << "\n\n Check whether a number is Disarium Number or not: \n"; // Display message about the program
    cout << " ---------------------------------------------------\n";
    cout << " Input a number: "; // Ask user to input a number
    cin >> dino; // Take user input

    // Check if the input number is a Disarium Number and display the result
    if (chkDisarum(dino))
        cout << " The given number is a Disarium Number." << endl;
    else
        cout << " The given number is not a Disarium Number." << endl;

    return 0; // Return 0 to indicate successful execution
}

Sample Output:

Check whether a number is Disarium Number or not:                                                   
 ---------------------------------------------------                                                 
 Input a number: 9                                                                                   
 The given number is a Disarium Number.

Flowchart:

C++ Code Editor:

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