C++ Exercises: Generate and show the first 15 Narcissistic decimal numbers

#include <iostream> // Include the input/output stream library
#include <cmath>    // Include the math library for mathematical operations
using namespace std; // Use the standard namespace

int main() 
{
    // Display a message for the user to find the first 15 Narcissistic decimal numbers
    cout << "\n\n Find the first 15 Narcissistic decimal numbers: \n";
    cout << " -----------------------------------------------------\n";
    // Display a message indicating the result will be the first 15 Narcissistic decimal numbers
    cout << " The first 15 Narcissistic decimal numbers are: \n";

    int i, ctr, j, orn, n, m, sum; // Declare integer variables for iteration and calculations
    orn = 1; // Set the initial number to check as 1

    // Loop to find the first 15 Narcissistic decimal numbers
    for (i = 1; i <= 15;) 
    {
        ctr = 0; // Initialize a counter for the number of digits in orn
        sum = 0; // Initialize a variable to store the sum of powers of digits

        n = orn; // Store the current number to check Narcissistic property

        // Calculate the number of digits (order) in the number
        while (n > 0) 
        {
            n = n / 10; // Reduce the number by one digit
            ctr++; // Increment the counter to count the digits
        }

        n = orn; // Reset the number for calculations

        // Calculate the sum of the powers of digits raised to the order
        while (n > 0) 
        {
            m = n % 10; // Extract the last digit of the number
            sum = sum + pow(m, ctr); // Add the m^ctr to the sum
            n = n / 10; // Reduce the number by one digit
        }

        // Check if the sum of powers of digits equals the original number (orn)
        if (sum == orn) 
        {
            cout << orn << " "; // If true, display the number as Narcissistic
            i++; // Increment the counter for found Narcissistic numbers
        }

        orn++; // Increment the original number for the next iteration
    }
    cout << endl; // Add a newline for better readability
}