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C++ Exercises: Compare two numbers

C++ For Loop: Exercise-82 with Solution

Write a program in C++ to compare two numbers.

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;
 
int main()
{
int num1,num2;
    cout << "\n\n Compare the first number with second number numbers:\n";
	cout << "---------------------------------------------------------\n";
	cout << " Input the first integer: ";
	cin>> num1;
	cout << " Input the second integer: ";
	cin>> num2;	
	
		if ( num1 == num2 )           
            cout<< num1<< " == " << num2 <<endl;  
        if ( num1 != num2 )          
            cout<< num1<<" != " << num2<<endl; 
        if ( num1 < num2 )          
            cout<< num1<< " < "<<num2<<endl; 
        if ( num1 > num2 )          
            cout<< num1<<" > "<< num2 <<endl; 
        if ( num1 <= num2 )          
            cout<<num1<<" <= "<< num2<<endl; 
        if ( num1 >= num2 )          
            cout<<num1<< " >= "<< num2<<endl; 	
}

Sample Output:

 Compare the first number with second number numbers:                  
---------------------------------------------------------              
 Input the first integer: 25                                           
 Input the second integer: 15                                          
25 != 15                                                               
25 > 15                                                                
25 >= 15

Flowchart:

Flowchart: Compare two numbers

C++ Code Editor:

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Previous: Write a program in C++ to convert a hexadecimal number to octal number.
Next: Write a program in C++ to compute the sum of the digits of an integer.

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C++ Programming: Tips of the Day

What is the "-->" operator in C/C++?

--> is not an operator. It is in fact two separate operators, -- and >.

The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.

To better understand, the statement could be written as follows:

while( (x--) > 0 )

Ref : https://bit.ly/3kOTBby





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