C++ Exercises: Display such a pattern for n number of rows using number
C++: For Loop Exercise-47 with Solution
Write a program in C++ to display such a pattern for n number of rows using numbers. Odd numbers will appear in each row. The first and last number of each row will be 1 and the middle column will be the row number.
Sample Solution:
C++ Code :
#include <iostream> // Include the input/output stream library
using namespace std; // Using standard namespace
int main() // Main function where the execution of the program starts
{
int i, j, n; // Declare integer variables i, j, and n
// Display message asking for input
cout << "\n\n Display a pattern using odd number of numbers, the first and last number of each row is 1:\n";
cout << "-----------------------------------------------------------------------------------------------\n";
cout << " Input number of rows: ";
cin >> n; // Read input for the number of rows from the user
for (i = 0; i <= n; i++) // Loop for the number of rows
{
/* print blank spaces */
for (j = 1; j <= n - i; j++) // Loop to print spaces before the numbers
cout << " "; // Print a space
/* Display numbers in ascending order up to the middle */
for (j = 1; j <= i; j++) // Loop to print numbers in ascending order
cout << j; // Print the number
/* Display numbers in reverse order after the middle */
for (j = i - 1; j >= 1; j--) // Loop to print numbers in reverse order
cout << j; // Print the number in reverse order
cout << endl; // Move to the next line after each row is printed
}
}
Sample Output:
Display a pattern using odd number of numbers, the first and last number of each row is 1: ----------------------------------------------------------------------------------------------- Input number of rows: 5 1 121 12321 1234321 123454321
Flowchart:
C++ Code Editor:
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