C++ Exercises: Find the number and sum of all integer between 100 and 200 which are divisible by 9
C++ For Loop: Exercise-28 with Solution
Write a program in C++ to find the number and sum of all integers between 100 and 200 which are divisible by 9.
Pictorial Presentation:

Sample Solution:-
C++ Code :
#include <iostream>
using namespace std;
int main()
{
int i, sum = 0;
cout << "\n\n Find the number and sum of all integer between 100 and 200, divisible by 9:\n";
cout << "--------------------------------------------------------------------------------\n";
cout << " Numbers between 100 and 200, divisible by 9: " << endl;
for (i = 101; i < 200; i++)
{
if (i % 9 == 0)
{
cout << " " << i;
sum += i;
}
}
cout << "\n The sum : " << sum << endl;
}
Sample Output:
Find the number and sum of all integer between 100 and 200, divisible by 9: -------------------------------------------------------------------------------- Numbers between 100 and 200, divisible by 9: 108 117 126 135 144 153 162 171 180 189 198 The sum : 1683
Flowchart:

C++ Code Editor:
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Previous: Write a program in C++ to display the first n terms of Fibonacci series.
Next: Write a program in C++ to find LCM of any two numbers using HCF.
What is the difficulty level of this exercise?
C++ Programming: Tips of the Day
What is the "-->" operator in C/C++?
--> is not an operator. It is in fact two separate operators, -- and >.
The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.
To better understand, the statement could be written as follows:
while( (x--) > 0 )
Ref : https://bit.ly/3kOTBby
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