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C++ Exercises: Display the sum of the specified series

C++ For Loop: Exercise-23 with Solution

Write a program in C++ to display the sum of the series [ 9 + 99 + 999 + 9999 ...].

Pictorial Presentation:

C++ Exercises: Display the sum of the specified series

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;

int main()
{
    long int n, i, t = 9;
    int sum = 0;
    cout << "\n\n Display the sum of the series [ 9 + 99 + 999 + 9999 ...]\n";
    cout << "-------------------------------------------------------------\n";
    cout << " Input number of terms: ";
    cin >> n;

    for (i = 1; i <= n; i++) 
    {
        sum += t;
        cout << t << "  ";
        t = t * 10 + 9;
    }
    cout << "\n The sum of the sarise = " << sum << endl;
}

Sample Output:

 Display the sum of the series [ 9 + 99 + 999 + 9999 ...]              
-------------------------------------------------------------          
 Input number of terms: 5                                              
9  99  999  9999  99999                                                
 The sum of the sarise = 111105   

Flowchart:

Flowchart: Display the sum of the specified series

C++ Code Editor:

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Next: Write a program in C++ to display the sum of the series [ 1+x+x^2/2!+x^3/3!+....].

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C++ Programming: Tips of the Day

What is the "-->" operator in C/C++?

--> is not an operator. It is in fact two separate operators, -- and >.

The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.

To better understand, the statement could be written as follows:

while( (x--) > 0 )

Ref : https://bit.ly/3kOTBby





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