﻿ C++ : Find the sum of the series 1+ 1/2^2 + 1/3^3 +..+ 1/n^n

# C++ Exercises: Find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n

## C++ For Loop: Exercise-11 with Solution

Write a program in C++ to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.

Pictorial Presentation:

Sample Solution :-

C++ Code :

``````#include <iostream>
#include <math.h>
using namespace std;

int main()
{
double sum = 0, a;
int n, i;
cout << "\n\n Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n:\n";
cout << "----------------------------------------------------------------\n";
cout << " Input the value for nth term: ";
cin >> n;
for (i = 1; i <= n; ++i)
{
a = 1 / pow(i, i);
cout << "1/" << i << "^" << i << " = " << a << endl;
sum += a;
}
cout << " The sum of the above series is: " << sum << endl;
}
``````

Sample Output:

``` Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n:
----------------------------------------------------------------
Input the value for nth term: 5
1/1^1 = 1
1/2^2 = 0.25
1/3^3 = 0.037037
1/4^4 = 0.00390625
1/5^5 = 0.00032
The sum of the above series is: 1.29126
```

Flowchart:

C++ Code Editor:

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## C++ Programming: Tips of the Day

Why is there no std::stou?

The most pat answer would be that the C library has no corresponding "strtou", and the C++11 string functions are all just thinly veiled wrappers around the C library functions: The std::sto* functions mirror strto*, and the std::to_string functions use sprintf.

Ref: https://bit.ly/3wtz2qA

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