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C++ Exercises: Find the total number of minutes between two given times

C++ Basic: Exercise-85 with Solution

Write a C++ program to find the total number of minutes between two given times (formatted with a colon and am or pm).

Pictorial Presentation:

C++ Exercises: Find the total number of minutes between two given times

Sample Solution:

C++ Code :

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

int count_minutes(string time_str) {

	string num1, num2;
	string hr1, hr2, min1, min2;
	int index = time_str.find('-');
	bool colon = false;

	for (int x = 0; x < time_str.length(); x++)
	{
		if (x >= index)
		{
			colon = false;
			for (x; x < time_str.length(); x++)
			{
				if (time_str[x] == ':')
				{
					colon = true;
					continue;
				}

				if (time_str[x] == 'A' || time_str[x] == 'P')
				{
					num2.push_back(time_str[x]);
					num2.push_back(time_str[x + 1]);
				}

				if (colon && isdigit(time_str[x]))
				{
					min2.push_back(time_str[x]);
				}
				else if (isdigit(time_str[x]))
				{
					hr2.push_back(time_str[x]);
				}
			}
		}
		else
		{
			if (time_str[x] == ':')
			{
				colon = true;
				continue;
			}

			if (time_str[x] == 'A' || time_str[x] == 'P')
			{
				num1.push_back(time_str[x]);
				num1.push_back(time_str[x + 1]);
			}

			if (colon && isdigit(time_str[x]))
			{
				min1.push_back(time_str[x]);
			}
			else if (isdigit(time_str[x]))
			{
				hr1.push_back(time_str[x]);
			}
		}
	}

	int hr = 0;
	if (stoi(hr1) == stoi(hr2) && num1 == num2 && stoi(min1) > stoi(min2))
	{
		hr = 24 - (stoi(hr1) - stoi(hr2));
	}
	else if (stoi(hr1) > stoi(hr2) && num1 == num2 && stoi(min1) < stoi(min2))
	{
		hr = 24 - (stoi(hr1) - stoi(hr2));
	}
	else if (num1 == num2 || (hr2 == "12" && hr1 != "12"))
	{
		hr = stoi(hr2) - stoi(hr1);
	}
	else
	{
		hr = (12 - stoi(hr1)) + stoi(hr2);
	}

	int time;
	if (min1 != "00")
	{
		time = (hr * 60 - stoi(min1)) + stoi(min2);
	}
	else
	{
		time = (hr * 60 + stoi(min1)) + stoi(min2);
	}

	return time;
}

int main() {

	cout << "Minutes between 12:01AM to 12:00PM: "<< count_minutes("12:01PM-12:00PM") << endl;
	cout << "Minutes between 2:12AM to 2:8AM: "<< count_minutes("2:12AM-2:8AM") << endl;
	cout << "Minutes between 1:04PM to 1:29PM: "<< count_minutes("1:04PM-1:29PM") << endl;
	cout << "Minutes between 2:00PM to 10:00PM: "<< count_minutes("2:00PM-10:00PM") << endl;
	return 0;
}

Sample Output:

Minutes between 12:01AM to 12:00PM: 1439
Minutes between 2:12AM to 2:8AM: 1436
Minutes between 1:04PM to 1:29PM: 25
Minutes between 2:00PM to 10:00PM: 480

Flowchart:

Flowchart: Find the total number of minutes between two given times.

C++ Code Editor:

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Previous C++ Exercise: Convert a given number into hours and minutes.

Next C++ Exercise: Add up all the digits between two numbers .

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C++ Programming: Tips of the Day

Why is there no std::stou?

The most pat answer would be that the C library has no corresponding "strtou", and the C++11 string functions are all just thinly veiled wrappers around the C library functions: The std::sto* functions mirror strto*, and the std::to_string functions use sprintf.

Ref: https://bit.ly/3wtz2qA

 





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