﻿ C++ : Print mode values of the sequence of integers

# C++ Exercises: Reads a sequence of integers and prints mode values of the sequence

## C++ Basic: Exercise-71 with Solution

Write a C++ program that reads a sequence of integers and prints the mode values of the sequence. The number of integers is greater than or equal to 1 and less than or equal to 100.
Note: The mode of a set of data values is the value that appears most often.

Sample Solution:

C++ Code :

``````#include <iostream>
#include <vector>
using namespace std;

int main() {
vector<int> nums(101, 0);
int n, mode=0;

while (cin >> n) {
nums[n]++;
if (nums[n] > mode) { mode=nums[n]; }
}

for (int i = 0; i != nums.size(); ++i) {
if (nums[i] == mode)
{
cout << i << endl;

}
}

return 0;
}
``````

Sample Output:

```0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
```

Flowchart:

C++ Code Editor:

What is the difficulty level of this exercise?

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## C++ Programming: Tips of the Day

Why is there no std::stou?

The most pat answer would be that the C library has no corresponding "strtou", and the C++11 string functions are all just thinly veiled wrappers around the C library functions: The std::sto* functions mirror strto*, and the std::to_string functions use sprintf.

Ref: https://bit.ly/3wtz2qA

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