C++ Exercises: Check a given array of integers, length 3 and create a new array

C++ Basic Algorithm: Exercise-92 with Solution

Replace '7' with '1' if Preceded by '5'

Write a C++ program to check a given array of integers, length 3 and create an array. If there is a 5 in the given array immediately followed by a 7 then set 7 to 1.

Sample Solution:

C++ Code :

#include <iostream> // Including the input/output stream library
using namespace std; // Using the standard namespace

// Function to modify the array nums by replacing '7' with '1' if preceded by '5'
int *test(int nums[], int arr_length) {
    for (int i = 0; i < arr_length - 1; i++) {
        if (nums[i] == 5 && nums[i + 1] == 7) // If the current element is '5' and the next element is '7'
            nums[i + 1] = 1; // Replace '7' with '1'
    }
    return nums; // Return the modified array
}

// Main function
int main() {
    int *p; // Declare a pointer to an integer
    int nums1[] = {1, 5, 7}; // Define an array nums1
    int arr_length = sizeof(nums1) / sizeof(nums1[0]); // Calculate the length of nums1

    p = test(nums1, arr_length); // Call the test function with nums1

    cout << "\nNew array: " << endl; // Output message for the new array
    for (int i = 0; i < arr_length; i++) {
        cout << *(p + i) << " "; // Output the elements of the modified array nums1
    }

    int nums2[] = {1, 5, 3, 7}; // Define another array nums2
    arr_length = sizeof(nums2) / sizeof(nums2[0]); // Calculate the length of nums2

    p = test(nums2, arr_length); // Call the test function with nums2

    cout << "\nNew array: " << endl; // Output message for the new array
    for (int i = 0; i < arr_length; i++) {
        cout << *(p + i) << " "; // Output the elements of the modified array nums2
    }

    return 0; // Return statement indicating successful termination of the program
}

Sample Output:

New array:
1 5 1
New array:
1 5 3 7

Visual Presentation:

Flowchart:

C++ Code Editor:

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