C++ Exercises: Check a given array of integers and return true if the array contains 10 or 20 twice

Last update on December 20 2024 12:22:15 (UTC/GMT +8 hours)

Check Array for Two 10s or 20s

Write a C++ program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.

Sample Solution:

C++ Code :

#include <iostream> // Including the input/output stream library
using namespace std; // Using the standard namespace

// Function to check if the array has exactly two elements and both are either 10 or both are 20
bool test(int nums[], int arr_length) {
    return arr_length == 2
&& ((nums[0] == 10 && nums[1] == 10)
             || (nums[0] == 20 && nums[1] == 20));
}

// Main function
int main () {
    int nums1[] = {12, 20}; // Define an array nums1
    int arr_length = sizeof(nums1) / sizeof(nums1[0]); // Calculate the length of nums1
    cout << test(nums1, arr_length) << endl; // Output the result of test function for nums1

    int nums2[] = {20, 20}; // Define an array nums2
    arr_length = sizeof(nums2) / sizeof(nums2[0]); // Calculate the length of nums2
    cout << test(nums2, arr_length) << endl; // Output the result of test function for nums2

    int nums3[] = {10, 10}; // Define an array nums3
    cout << test(nums3, arr_length) << endl; // Output the result of test function for nums3

    int nums4[] = {10}; // Define an array nums4
    arr_length = sizeof(nums4) / sizeof(nums4[0]); // Calculate the length of nums4
    cout << test(nums4, arr_length) << endl; // Output the result of test function for nums4

    return 0; // Return statement indicating successful termination of the program
}

Sample Output:

0
1
1
0

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