C++ Exercises: Check two given integers and return the value whichever value is nearest to 13 without going over

Last update on April 07 2025 12:57:59 (UTC/GMT +8 hours)

Nearest to 13 Without Crossing Over

Write a C++ program to check two integers and return the value nearest to 13 without crossing over. Return 0 if both numbers go over.

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;

// Class Solution contains a function to manipulate numbers
class Solution
{
public:
    // Function 'test' takes three integers (x, y, z) as parameters
    int test(int x, int y, int z)
    {
        return fix_num(x) + fix_num(y) + fix_num(z); // Returns the sum after applying fix_num to each number
    }

    // Function 'fix_num' takes an integer 'n' as a parameter and processes it
    int fix_num(int n)
    {
        // Checks if 'n' falls within certain ranges and replaces it with 0 if it does
        return (n < 13 && n > 9) || (n > 17 && n < 21) ? 0 : n;
    }
};

int main() 
{
    // Creating an instance of the Solution class
    Solution *solution = new Solution();

    // Testing the 'test' function with different sets of numbers
    cout << solution->test(4, 5, 7) << endl;
    cout << solution->test(7, 4, 12) << endl; 
    cout << solution->test(10, 13, 12) << endl;
    cout << solution->test(17, 12, 18) << endl;

    return 0;    
}

Sample Output:

16
11
13
17

Visual Presentation:

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C++ program to compare two integers and return the one closest to 13 without exceeding 13; return 0 if both are greater than 13.
• Write a C++ program that reads two numbers and outputs the value nearest to 13 provided it does not cross over, else returns 0.
• Write a C++ program to determine which of two inputs is closest to 13 without going over 13, and print 0 if both exceed it.
• Write a C++ program that accepts two integers and checks if either is less than or equal to 13, returning the closest one to 13 or 0 if both are above.

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