# C++ Exercises: Check three given integers and return true if one of them is 20 or more less than one of the others

## C++ Basic Algorithm: Exercise-48 with Solution

Write a C++ program to check three given integers and return true if one of them is 20 lower than one of the others.

**Sample Solution**:

**C++ Code :**

```
#include <iostream>
using namespace std;
bool test(int x, int y, int z)
{
return abs(x - y) >= 20 || abs(x - z) >= 20 ||
abs(y - z) >= 20;
}
int main()
{
cout << test(11, 21, 31) << endl;
cout << test(11, 22, 31) << endl;
cout << test(10, 20, 15) << endl;
return 0;
}
```

Sample Output:

1 1 0

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**C++ Code Editor:**

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**Previous:** Write a C++ program to check if two or more non-negative given integers have the same rightmost digit.

**Next:** Write a C++ program to find the larger from two given integers. However if the two integers have the same remainder when divided by 7, then the return the smaller integer. If the two integers are the same, return 0.

**What is the difficulty level of this exercise?**

## C++ Programming: Tips of the Day

**What is the "-->" operator in C/C++?**

--> is not an operator. It is in fact two separate operators, -- and >.

The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.

To better understand, the statement could be written as follows:

while( (x--) > 0 )

Ref : https://bit.ly/3kOTBby

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