C++ Exercises: Check if a triple is presents in an array of integers or not

C++ Basic Algorithm: Exercise-36 with Solution

Write a C++ program to check if a triple is present in an array of integers or not. If a value appears three times in a row in an array it is called a triple.

Sample Solution:

C++ Code :

#include <iostream>
 
using namespace std;

bool test(int nums[], int arr_length)
        {
            int arra_len = arr_length - 1;
			int n = 0;
			for (int i = 0; i < arra_len; i++)
            {
                 n = nums[i];
				if (n == nums[i + 1] && n == nums[i + 2]) return true;
            }
            return false;
        }
        
int main() 
 {
  int arr_length;	
  int nums1[] = {1, 1, 2, 2, 1};	
  arr_length = sizeof(nums1) / sizeof(nums1[0]);
  cout << test(nums1, arr_length) << endl; 
  int nums2[] = {1, 1, 2, 1, 2, 3};	
  arr_length = sizeof(nums2) / sizeof(nums2[0]);
  cout << test(nums2, arr_length) << endl;
  int nums3[] = {1, 1, 1, 2, 2, 2, 1};	
  arr_length = sizeof(nums3) / sizeof(nums3[0]);
  cout << test(nums3, arr_length) << endl;
  return 0;   
}

Sample Output:

0
0
1

Pictorial Presentation:

Flowchart:

C++ Code Editor:

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