﻿ C++ : Check if a triple is presents in an array or not

# C++ Exercises: Check if a triple is presents in an array of integers or not

## C++ Basic Algorithm: Exercise-36 with Solution

Write a C++ program to check if a triple is present in an array of integers or not. If a value appears three times in a row in an array it is called a triple.

Sample Solution:

C++ Code :

#include <iostream>

using namespace std;

bool test(int nums[], int arr_length)
{
int arra_len = arr_length - 1;
int n = 0;
for (int i = 0; i < arra_len; i++)
{
n = nums[i];
if (n == nums[i + 1] && n == nums[i + 2]) return true;
}
return false;
}

int main()
{
int arr_length;
int nums1[] = {1, 1, 2, 2, 1};
arr_length = sizeof(nums1) / sizeof(nums1[0]);
cout << test(nums1, arr_length) << endl;
int nums2[] = {1, 1, 2, 1, 2, 3};
arr_length = sizeof(nums2) / sizeof(nums2[0]);
cout << test(nums2, arr_length) << endl;
int nums3[] = {1, 1, 1, 2, 2, 2, 1};
arr_length = sizeof(nums3) / sizeof(nums3[0]);
cout << test(nums3, arr_length) << endl;
return 0;
}

Sample Output:

0
0
1

Pictorial Presentation:

Flowchart:

C++ Code Editor:

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## C++ Programming: Tips of the Day

Converting an int to std::string

You can use std::to_string in C++11

int i = 3;
std::string str = std::to_string(i);

Ref : https://bit.ly/3vd2Kjy

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