C++ Exercises: Find the largest average value between the first and second halves of a given array of integers

Last update on December 20 2024 12:27:53 (UTC/GMT +8 hours)

Find Larger Average Between First and Second Halves of Array

Write a C++ program to find the largest average value between the first and second halves of a given array of integers. Ensure that the minimum length is at least 2. Assume that the second half begins at index (array length)/2.

Test Data:
({ 1, 2, 3, 4, 6, 8 }) -> 6
({ 15, 2, 3, 4, 15, 11 }) -> 10

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Forward declaration of function avgg
int avgg(int[], int, int, size_t);

// Function to find the larger average value between the first and second halves of an array
int test(int numbers[], int arr_length) {
    // Finding the average of the first half
    int firstHalf = avgg(numbers, 0, arr_length / 2, arr_length);
    // Finding the average of the second half
    int secondHalf = avgg(numbers, arr_length / 2, arr_length, arr_length);
    // Returning the larger of the two averages
    return firstHalf > secondHalf ? firstHalf : secondHalf;
}

// Function to calculate the average of elements within a specified range
int avgg(int num[], int start, int end, size_t arr_length) {
    int sum = 0;
    // Calculating the sum of elements within the range
    for (int i = start; i < end; i++)
        sum += num[i];
    // Calculating and returning the average
    return sum / (arr_length / 2);
}

// Main function
int main() {
    // First test array
    int nums1[] = {1, 2, 3, 4, 6, 8 };
    size_t arr_length = sizeof(nums1) / sizeof(int);
    // Displaying original array elements
    cout << "Original array elements: ";
    for (size_t i = 0; i < arr_length; i++) {
        std::cout << nums1[i] << ' ';
    }
    // Finding and displaying the larger average value between the first and second halves
    cout << "\nLarger average value between the first and the second half of the said array: ";
    cout << test(nums1, arr_length) << endl;

    // Second test array
    int nums2[] = { 15, 2, 3, 4, 15, 11 };
    arr_length = sizeof(nums2) / sizeof(int);
    // Displaying original array elements
    cout << "\nOriginal array elements: ";
    for (size_t i = 0; i < arr_length; i++) {
        std::cout << nums2[i] << ' ';
    }
    // Finding and displaying the larger average value between the first and second halves
    cout << "\nLarger average value between the first and the second half of the said array: ";
    cout << test(nums2, arr_length) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

Original array elements: 1 2 3 4 6 8 
Larger average value between the first and the second half of the said array: 6

Original array elements: 15 2 3 4 15 11 
Larger average value between the first and the second half of the said array: 10

Flowchart:

C++ Code Editor:

Contribute your code and comments through Disqus.

Previous: Check if there are two values 15, 15 adjacent to each other in a given array of integers.
Next: Count the number of strings with a given length in an array.