C++ Exercises: Check if the value of each element is equal or greater than the value of previous element of a given array of integers

Last update on December 20 2024 12:27:52 (UTC/GMT +8 hours)

Check if Array is Non-Decreasing

Write a C++ program to check if the value of each element is equal or greater than the value of the previous element of a given array of integers.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function to check if the elements in the array are in ascending order
static bool test(int numbers[], int arr_length)
{
    for (int i = 0; i < arr_length - 1; i++)
    {
        if (numbers[i + 1] < numbers[i]) return false;  // If the next element is smaller than the current element, return false
    }

    return true;  // Return true if all elements are in ascending order
}   

// Main function
int main() 
 {  
    // Different test cases with arrays of integers
    int nums1[] = {5, 5, 1, 5, 5};  // Not in ascending order
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length) << endl; 

    int nums2[] = {1, 2, 3, 4 };  // In ascending order
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length) << endl;

    int nums3[] = {3, 3, 5, 5, 5, 5};  // In ascending order
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length) << endl;

    int nums4[] = {1, 5, 5, 7, 8, 10};  // In ascending order
    arr_length = sizeof(nums4) / sizeof(nums4[0]);
    cout << test(nums4, arr_length) << endl;  

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

Flowchart:

C++ Code Editor:

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