C++ Exercises: Check a given array of integers and return true if the array contains three increasing adjacent numbers

Last update on December 20 2024 12:27:52 (UTC/GMT +8 hours)

Check for Three Increasing Adjacent Numbers in Array

Write a C++ program to check a given array of integers and return true if the array contains three increasing adjacent numbers.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function to check if there are three consecutive elements in the array that are in increasing order
static bool test(int numbers[], int arr_length)
{
    for (int i = 0; i <= arr_length - 3; i++)
    {
        // Checking if the current element is one less than the next and also one less than the one after that
        if (numbers[i] == numbers[i + 1] - 1 && numbers[i] == numbers[i + 2] - 2)
        {
            return true;  // If found, return true
        }
    }
    return false;  // Return false if no such sequence is found
}   

// Main function
int main() 
{  
    // Different test cases with arrays of integers
    int nums1[] = {1, 2, 3, 5, 3, 7};  // Contains a sequence of 3 consecutive numbers (1, 2, 3)
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length) << endl; 

    int nums2[] = {3, 7, 5, 5, 3, 7 };  // Does not contain a sequence of 3 consecutive numbers
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length) << endl;

    int nums3[] = {3, 7, 5, 5, 6, 7, 5};  // Contains a sequence of 3 consecutive numbers (5, 6, 7)
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

1
0
1

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