C++ Exercises: Check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array

Last update on December 20 2024 12:21:25 (UTC/GMT +8 hours)

Check if Specified Elements Appear at Both Start and End of Array

Write a C++ program to check a given array of integers. The program will return true if the specified number of the same elements appears at the start and end of the given array.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function to check if the last 'n' elements in the array match the first 'n' elements
static bool test(int numbers[], int arr_length, int n)
{
    // Loop through the first 'n' elements and compare with the last 'n' elements
    for (int i = 0; i < n; i++)
    {
        // Check for inequality between elements from the beginning and end of the array
        if (numbers[i] != numbers[arr_length - n + i])
        {
            return false;  // Return false if inequality is found
        }
    }

    return true;  // Return true if all 'n' elements match between the two segments
}   

// Main function
int main() 
{  
    // Different test cases with arrays of integers and 'n' value
    int nums1[] = {3, 7, 5, 5, 3, 7 };  // Last 2 elements match the first 2 elements
    int n = 2;
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length, n) << endl; 

    int nums2[] = {3, 7, 5, 5, 3, 7};  // Last 3 elements do not match the first 3 elements
    n = 3;
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length, n) << endl;

    int nums3[] = {3, 7, 5, 5, 3, 7, 5};  // Last 3 elements match the first 3 elements
    n = 3;
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length, n) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

1
0
1

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