C++ Exercises: Check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array
C++ Basic Algorithm: Exercise-114 with Solution
Write a C++ program to check a given array of integers. The program will return true if the specified number of the same elements appears at the start and end of the given array.
Sample Solution:
C++ Code :
#include <iostream> // Including input-output stream header file
using namespace std; // Using standard namespace
// Function to check if the last 'n' elements in the array match the first 'n' elements
static bool test(int numbers[], int arr_length, int n)
{
// Loop through the first 'n' elements and compare with the last 'n' elements
for (int i = 0; i < n; i++)
{
// Check for inequality between elements from the beginning and end of the array
if (numbers[i] != numbers[arr_length - n + i])
{
return false; // Return false if inequality is found
}
}
return true; // Return true if all 'n' elements match between the two segments
}
// Main function
int main()
{
// Different test cases with arrays of integers and 'n' value
int nums1[] = {3, 7, 5, 5, 3, 7 }; // Last 2 elements match the first 2 elements
int n = 2;
int arr_length = sizeof(nums1) / sizeof(nums1[0]);
cout << test(nums1, arr_length, n) << endl;
int nums2[] = {3, 7, 5, 5, 3, 7}; // Last 3 elements do not match the first 3 elements
n = 3;
arr_length = sizeof(nums2) / sizeof(nums2[0]);
cout << test(nums2, arr_length, n) << endl;
int nums3[] = {3, 7, 5, 5, 3, 7, 5}; // Last 3 elements match the first 3 elements
n = 3;
arr_length = sizeof(nums3) / sizeof(nums3[0]);
cout << test(nums3, arr_length, n) << endl;
return 0; // Returning 0 to indicate successful completion of the program
}
Sample Output:
1 0 1
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