C++ Exercises: Check a given array of integers and return true if every 5 that appears in the given array is next to another 5
C++ Basic Algorithm: Exercise-113 with Solution
Write a C++ program to check a given array of integers and return true if every 5 that appears in the given array is next to another 5.
Sample Solution:
C++ Code :
#include <iostream>
using namespace std;
static bool test(int numbers[], int arr_length)
{
bool flag = true;
for (int i = 0; i < arr_length; i++)
{
if (numbers[i] == 5)
{
if ((i > 0 && numbers[i - 1] == 5) || (i < arr_length - 1 && numbers[i + 1] == 5)) flag = true;
else if (i == arr_length - 1) flag = false;
else return false;
}
}
return flag;
}
int main()
{
int nums1[] = {3, 5, 5, 3, 7};
int arr_length = sizeof(nums1) / sizeof(nums1[0]);
cout << test(nums1, arr_length) << endl;
int nums2[] = {3, 5, 5, 4, 1, 5, 7};
arr_length = sizeof(nums2) / sizeof(nums2[0]);
cout << test(nums2, arr_length) << endl;
int nums3[] = {3, 5, 5, 5, 5, 5};
arr_length = sizeof(nums3) / sizeof(nums3[0]);
cout << test(nums3, arr_length) << endl;
int nums4[] = {2, 4, 5, 5, 6, 7, 5};
arr_length = sizeof(nums4) / sizeof(nums4[0]);
cout << test(nums4, arr_length) << endl;
return 0;
}
Sample Output:
1 0 1 0
Pictorial Presentation:

Flowchart:

C++ Code Editor:
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Previous: Write a C++ program to check a given array of integers and return true if the value 5 appears 5 times and there are no 5 next to each other.
Next: Write a C++ program to check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array.
What is the difficulty level of this exercise?
C++ Programming: Tips of the Day
What is the "-->" operator in C/C++?
--> is not an operator. It is in fact two separate operators, -- and >.
The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.
To better understand, the statement could be written as follows:
while( (x--) > 0 )
Ref : https://bit.ly/3kOTBby
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