C++ Exercises: Check a given array of integers and return true if the value 5 appears 5 times and there are no 5 next to each other

Last update on December 20 2024 12:27:50 (UTC/GMT +8 hours)

Check if Five '5's Exist Without Adjacent Ones

Write a C++ program to check a given array of integers. The program will return true if the value 5 appears 5 times and there are no 5 next to each other.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function definition that checks if the number 5 appears exactly 5 times consecutively in the array
static bool test(int numbers[], int arr_length)
{
    bool flag = false;  // Flag to indicate if a sequence of 5s is encountered

    int five = 0;  // Counter to track the number of occurrences of 5

    // Loop through the array to find sequences of consecutive 5s
    for (int i = 0; i < arr_length; i++)
    {
        // Checking for the occurrence of 5 and handling the flag for consecutive 5s
        if (numbers[i] == 5 && !flag)
        {
            five++;       // Increment the count of 5s
            flag = true;  // Set flag to true indicating the start of a sequence of 5s
        }
        else
        {
            flag = false;  // Reset flag if the sequence is interrupted
        }
    }

    // Return true if the number 5 appears exactly 5 times consecutively, otherwise false
    return five == 5;
}

int main() 
{  
    // Different test cases with arrays of integers
    int nums1[] = {3, 5, 1, 5, 3, 5, 7, 5, 1, 5};  // 5 appears exactly 5 times consecutively
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length) << endl; 

    int nums2[] = {3, 5, 5, 5, 5, 5, 5};  // 5 appears more than 5 times consecutively
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length) << endl;

    int nums3[] = {3, 5, 2, 5, 4, 5, 7, 5, 8, 5};  // 5 appears more than 5 times consecutively
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length) << endl;

    int nums4[] = {2, 4, 5, 5, 5, 5};  // 5 appears exactly 5 times consecutively
    arr_length = sizeof(nums4) / sizeof(nums4[0]);
    cout << test(nums4, arr_length) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

1
0
1
0

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