﻿ C++ : If two even or two odd values are adjacent in an array

# C++ Exercises: Check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other

## C++ Basic Algorithm: Exercise-111 with Solution

Write a C++ program to check a given array of integers. The program will return true if the given array contains either 2 even or 2 odd values all next to each other.

Sample Solution:

C++ Code :

``````#include <iostream>
using namespace std;

static bool test(int numbers[], int arr_length)
{
int tot_odd = 0, tot_even = 0;

for (int i = 0; i < arr_length; i++)
{
if (tot_odd < 2 && tot_even < 2)
{
if (numbers[i] % 2 == 0)
{
tot_even++;
tot_odd = 0;
}
else
{
tot_odd++;
tot_even = 0;
}
}
}
}

int main()
{
int nums1[] = {3, 5, 1, 3, 7};
int arr_length = sizeof(nums1) / sizeof(nums1);
cout << test(nums1, arr_length) << endl;
int nums2[] = {1, 2, 3, 4};
arr_length = sizeof(nums2) / sizeof(nums2);
cout << test(nums2, arr_length) << endl;
int nums3[] = {3, 3, 5, 5, 5, 5};
arr_length = sizeof(nums3) / sizeof(nums3);
cout << test(nums3, arr_length) << endl;
int nums4[] = {2, 4, 5, 6};
arr_length = sizeof(nums4) / sizeof(nums4);
cout << test(nums4, arr_length) << endl;
return 0;
}
``````

Sample Output:

```1
0
1
1
```

Pictorial Presentation: Flowchart: C++ Code Editor:

What is the difficulty level of this exercise?

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## C++ Programming: Tips of the Day

What is the "-->" operator in C/C++?

--> is not an operator. It is in fact two separate operators, -- and >.

The conditional's code decrements x, while returning x's original (not decremented) value, and then compares the original value with 0 using the > operator.

To better understand, the statement could be written as follows:

while( (x--) > 0 )

Ref : https://bit.ly/3kOTBby

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