C Programming: Check whether a character is Hexadecimal Digit or not

Last update on December 20 2024 13:09:07 (UTC/GMT +8 hours)

Write a program in C to check whether a character is a Hexadecimal Digit or not.

Sample Solution:

C Code:

#include<stdio.h>
#include<ctype.h>

int main() {
    char TestChar; // Variable to store the input character

    printf("\n Check whether a character is Hexadecimal Digit or not :\n");
    printf("-------------------------------------------------------\n");
    printf(" Input a character : "); // Prompt user to input a character
    scanf("%c", &TestChar); // Read a character from the user

    // Check if the entered character is a hexadecimal digit
    if (isxdigit(TestChar)) {
        printf(" The entered character is a hexadecimal digit. \n"); // Display message if it is a hexadecimal digit
    } else {
        printf(" The entered character is not a hexadecimal digit. \n"); // Display message if it is not a hexadecimal digit
    }

    return 0; // Return 0 to indicate successful execution of the program
}

Sample Output:

 Check whether a character is Hexadecimal Digit or not :
-------------------------------------------------------
 Input a character : 7
 The entered character is a hexadecimal digit.

Flowchart :

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