C Exercises: Demonstrate the use of & and * operator

C Pointer : Exercise-3 with Solution

Write a program in C to demonstrate the use of the &(address of) and *(value at address) operators.

Visual Presentation:

Sample Solution:

C Code:

#include <stdio.h>

int main()
{
    int m = 300;     // Declare and initialize an integer variable m
    float fx = 300.60;  // Declare and initialize a float variable fx
    char cht = 'z';  // Declare and initialize a char variable cht

    printf("\n\n Pointer : Demonstrate the use of & and * operator :\n");
    printf("--------------------------------------------------------\n");

    int *pt1;     // Declare an integer pointer pt1
    float *pt2;   // Declare a float pointer pt2
    char *pt3;    // Declare a char pointer pt3

    pt1 = &m;     // Assign the address of m to pointer pt1
    pt2 = &fx;    // Assign the address of fx to pointer pt2
    pt3 = &cht;   // Assign the address of cht to pointer pt3

    printf(" m = %d\n", m);       // Print the value of m
    printf(" fx = %f\n", fx);     // Print the value of fx
    printf(" cht = %c\n", cht);   // Print the value of cht

    printf("\n Using & operator :\n");
    printf("-----------------------\n");
    printf(" address of m = %p\n", &m);   // Print the address of m
    printf(" address of fx = %p\n", &fx); // Print the address of fx
    printf(" address of cht = %p\n", &cht); // Print the address of cht

    printf("\n Using & and * operator :\n");
    printf("-----------------------------\n");
    printf(" value at address of m = %d\n", *(&m));   // Print the value at the address of m
    printf(" value at address of fx = %f\n", *(&fx)); // Print the value at the address of fx
    printf(" value at address of cht = %c\n", *(&cht)); // Print the value at the address of cht

    printf("\n Using only pointer variable :\n");
    printf("----------------------------------\n");
    printf(" address of m = %p\n", pt1);  // Print the address stored in pt1
    printf(" address of fx = %p\n", pt2); // Print the address stored in pt2
    printf(" address of cht = %p\n", pt3); // Print the address stored in pt3

    printf("\n Using only pointer operator :\n");
    printf("----------------------------------\n");
    printf(" value at address of m = %d\n", *pt1); // Print the value pointed by pt1
    printf(" value at address of fx= %f\n", *pt2); // Print the value pointed by pt2
    printf(" value at address of cht= %c\n\n", *pt3); // Print the value pointed by pt3
}

Sample Output:

Pointer : Demonstrate the use of & and * operator :                                                          
--------------------------------------------------------                                                      
 m = 300                                                                                                      
 fx = 300.600006                                                                                              
 cht = z                                                                                                      
                                                                                                              
 Using & operator :                                                                                           
-----------------------                                                                                       
 address of m = 0x7fff71cd0b38                                                                                
 address of fx = 0x7fff71cd0b3c                                                                               
 address of cht = 0x7fff71cd0b37                                                                              
                                                                                                              
 Using & and * operator :                                                                                     
-----------------------------                                                                                 
 value at address of m = 300                                                                                  
 value at address of fx = 300.600006                                                                          
 value at address of cht = z              

 Using only pointer variable :                                                                                
----------------------------------                                                                            
 address of m = 0x7fff71cd0b38                                                                                
 address of fx = 0x7fff71cd0b3c                                                                               
 address of cht = 0x7fff71cd0b37                                                                              
                                                                                                              
 Using only pointer operator :                                                                                
----------------------------------                                                                            
 value at address of m = 300                                                                                  
 value at address of fx= 300.600006                                                                           
 value at address of cht= z 
 

Flowchart:

C Programming Code Editor:

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