C Exercises: Swap elements using call by reference
C Pointer : Exercise-11 with Solution
Write a program in C to swap elements using call by reference.
Visual Presentation:
Sample Solution:
C Code:
#include <stdio.h>
// Function prototype to swap elements using call by reference
void swapNumbers(int *x, int *y, int *z);
int main() {
int e1, e2, e3;
printf("\n\n Pointer : Swap elements using call by reference :\n");
printf("------------------------------------------------------\n");
// Input three integer values from the user
printf(" Input the value of 1st element : ");
scanf("%d", &e1);
printf(" Input the value of 2nd element : ");
scanf("%d", &e2);
printf(" Input the value of 3rd element : ");
scanf("%d", &e3);
printf("\n The value before swapping are :\n");
printf(" element 1 = %d\n element 2 = %d\n element 3 = %d\n", e1, e2, e3);
// Call the function to swap the values of the three elements
swapNumbers(&e1, &e2, &e3);
printf("\n The value after swapping are :\n");
printf(" element 1 = %d\n element 2 = %d\n element 3 = %d\n\n", e1, e2, e3);
return 0;
}
// Function definition to swap the values of three integer pointers
void swapNumbers(int *x, int *y, int *z) {
int tmp;
tmp = *y;
*y = *x;
*x = *z;
*z = tmp;
}
Sample Output:
Pointer : Swap elements using call by reference : ------------------------------------------------------ Input the value of 1st element : 5 Input the value of 2nd element : 6 Input the value of 3rd element : 7 The value before swapping are : element 1 = 5 element 2 = 6 element 3 = 7 The value after swapping are : element 1 = 7 element 2 = 5 element 3 = 6
Flowchart:
C Programming Code Editor:
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