C Exercises: Find Pronic Number between 1 to 1000

Last update on December 20 2024 13:06:57 (UTC/GMT +8 hours)

Write a program in C to find a Pronic Number between 1 and 1000.

Sample Solution:

C Code:

# include <stdio.h>
# include <stdlib.h>

int main()
{
    int prno, i, n, flg;  // Variable declaration: prno is the number being checked, i is a loop variable, n is not used, flg is a flag for checking

    // Printing information about the program
    printf("\n\n Find the Pronic Numbers between 1 to 1000: \n");
    printf(" -----------------------------------------------\n");
    printf(" The Pronic numbers are: \n");

    for (prno = 1; prno <= 1000; prno++)  // Loop to check for Pronic Numbers from 1 to 1000
    {
        flg = 0;  // Initializing flag to 0 for each number 'prno'

        for (i = 1; i <= prno; i++)  // Inner loop to check if 'prno' is a Pronic Number
        {
            if (i * (i + 1) == prno)  // Checking if 'prno' is a product of consecutive numbers
            {
                flg = 1;  // Setting flag to 1 if 'prno' is a Pronic Number
                break;    // Exiting the inner loop if condition is met
            }
        }

        if (flg == 1)  // Checking the flag value to determine if 'prno' is a Pronic Number
        {
            printf("%d ", prno);  // Printing 'prno' if it's a Pronic Number
        }
    }

    printf("\n");  // Print a new line after displaying all Pronic Numbers between 1 and 1000

    return 0;  // Returning 0 to indicate successful execution
}

Sample Output:

The Pronic numbers are:                                                                                      
2 6 12 20 30 42 56 72 90 110 132 156 182 210 240 272 306 342 380 420 462 506 552 600 650 
702 756 812 870 930 992 

Visual Presentation:

Flowchart:

C Programming Code Editor:

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