C Exercises: Check whether a given number is Abundant or not

Last update on December 20 2024 13:06:56 (UTC/GMT +8 hours)

Write a program in C to check whether a given number is Abundant or not.

Test Data
Input an integer number: 18

Sample Solution:

C Code:

#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include <math.h>

// Function to calculate the sum of divisors of a number
int getSum(int n)
{
    int sum = 0;
    for (int i = 1; i <= sqrt(n); i++) // Loop through numbers from 1 to the square root of 'n'
    {
        if (n % i == 0) // Check if 'i' is a divisor of 'n'
        {
            if (n / i == i)
                sum = sum + i; // If 'i' is a divisor and is equal to the square root of 'n', add it to 'sum'
            else
            {
                sum = sum + i; // Add 'i' to 'sum'
                sum = sum + (n / i); // Add 'n / i' to 'sum'
            }
        }
    }
    sum = sum - n; // Subtract the number 'n' from the sum of its divisors
    return sum; // Return the sum of divisors
}

// Function to check if a number is an abundant number
bool checkAbundant(int n)
{
    return getSum(n) > n; // Return true if the sum of divisors is greater than 'n', otherwise return false
}

// Main function
int main()
{
    int n;
    printf("\n\n Check whether a given number is an Abundant number:\n");
    printf(" --------------------------------------------------------\n");
    printf(" Input an integer number: ");
    scanf("%d", &n); // Read an integer from the user and store it in variable 'n'

    // Check if the number is abundant and print the result
    checkAbundant(n) ? printf(" The number is Abundant.\n") : printf(" The number is not Abundant.\n");

    return 0;
}

Sample Output:

 Input an integer number: 18                                                                                  
 The number is Abundant.  

Visual Presentation:

Flowchart:

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