C Exercises: Find cube of the number upto a given integer
C For Loop: Exercise-5 with Solution
Write a program in C to display the cube of the number up to an integer.
This C program calculates and displays the cube of each number up to a given integer. It uses a "for" loop to iterate through each number from 1 to the specified integer, computes the cube by raising the number to the power of three, and then prints the result.
Visual Presentation:
Sample Solution:
C Code:
#include <stdio.h> // Include the standard input/output header file.
void main() {
int i, ctr; // Declare variables 'i' for loop counter and 'ctr' for user input.
printf("Input number of terms : "); // Print a message to prompt user input.
scanf("%d", &ctr); // Read the value of 'ctr' from the user.
for (i = 1; i <= ctr; i++) { // Start a for loop to iterate 'ctr' times.
printf("Number is : %d and cube of the %d is :%d \n", i, i, (i * i * i)); // Print the number, its cube, and message.
}
}
Output:
Input number of terms : 5 Number is : 1 and cube of the 1 is :1 Number is : 2 and cube of the 2 is :8 Number is : 3 and cube of the 3 is :27 Number is : 4 and cube of the 4 is :64 Number is : 5 and cube of the 5 is :125
Explanation:
for (i = 1; i <= ctr; i++) { printf("Number is : %d and cube of the %d is :%d \n", i, i, (i * i * i)); }
In the above for loop, the variable i is initialized to 1, and the loop will continue as long as i is less than or equal to the value of variable 'ctr'. In each iteration of the loop, the printf function will print a formatted string to the console. The string will display the value of i twice and the cube of i.
The first placeholder %d will be replaced by the value of i, the second placeholder %d will also be replaced by the value of i, and the third placeholder %d will be replaced by the cube of i (i.e., i * i * i).
The loop will increment the value of i by 1, and the process will repeat until the condition i<=ctr is no longer true.
Flowchart:
C Programming Code Editor:
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