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C Exercises: Find the number and sum of all integer between 100 and 200, divisible by 9

C For Loop: Exercise-39 with Solution

Write a program in C to find the number and sum of all integers between 100 and 200 which are divisible by 9.

The program should iterate through the numbers within the specified range, checking if each number is divisible by 9. If a number meets this condition, it should be included in the count, and its value should be added to the sum. Finally, the program will display the total count of such numbers and their sum.

Visual Presentation:

Check whether a number is a palindrome or not

C Code:

#include <stdio.h> // Include the standard input/output header file.

void main()
{
   int i, sum=0; // Declare variables for iteration and sum.

   printf("Numbers between 100 and 200, divisible by 9 : \n"); // Print a message to indicate the output format.

   for(i=101; i<200; i++) // Loop through numbers from 101 to 199.
   {
     if(i%9==0) // Check if the current number is divisible by 9.
     {
       printf("% 5d", i); // Print the number with formatting.
       sum += i; // Add the divisible number to the sum.
     }
   }

   printf("\n\nThe sum : %d \n", sum); // Print the total sum of divisible numbers.
}

Output:

Numbers between 100 and 200, divisible by 9 :                                                                 
  108  117  126  135  144  153  162  171  180  189  198                                                       
                                                                                                              
The sum : 1683 

Flowchart:

Flowchart : Find the number and sum of all integer between 100 and 200, divisible by 9

C Programming Code Editor:

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