C Exercises: Find the Armstrong number for a given range of number

/* 
   When the sum of the cube of the individual digits of a number 
   is equal to that number, the number is called Armstrong number. 
   For example 153. Sum of its divisor is 13 + 53 + 33 = 1 + 125 + 27 = 153
*/
#include <stdio.h> // Include the standard input/output header file.

void main(){
    int num, r, sum, temp; // Declare variables for the input number, remainder, sum, and a temporary variable.
    int stno, enno; // Declare variables for the starting and ending range.

    printf("Input starting number of range: "); // Prompt the user to input the starting range.
    scanf("%d", &stno); // Read the starting range from the user.

    printf("Input ending number of range : "); // Prompt the user to input the ending range.
    scanf("%d", &enno); // Read the ending range from the user.

    printf("Armstrong numbers in given range are: "); // Print a message indicating that Armstrong numbers will be displayed.

    for(num = stno; num <= enno; num++){ // Start a loop to iterate through the numbers in the specified range.
        temp = num; // Set 'temp' to the current number for manipulation.
        sum = 0; // Initialize 'sum' to zero.

        while(temp != 0){ // Start a loop to extract digits from 'temp'.
            r = temp % 10; // Get the last digit of 'temp'.
            temp = temp / 10; // Remove the last digit from 'temp'.
            sum = sum + (r * r * r); // Calculate the sum of cubes of each digit.
        }

        if(sum == num) // If the sum of cubes of digits is equal to the original number.
            printf("%d ", num); // Print the number, as it's an Armstrong number.
    }

    printf("\n"); // Print a newline to separate the output.
}