C Exercises: Display the sum of first 10 natural numbers
C For Loop: Exercise-2 with Solution
Write a C program to compute the sum of the first 10 natural numbers.
This C program calculates the sum of the first 10 natural numbers. It utilizes a "for" loop to iterate through numbers 1 to 10, accumulating their sum, and then prints the total. This exercise is helpful for understanding basic loop constructs and arithmetic operations in C.
Visual Presentation:
Pseudo code to find the sum of the first 10 natural numbers:
- Initialize a variable "sum" to 0
- Initialize a loop variable "i" to 1
- Repeat the following steps while i <= 10: a. Add i to the sum variable b. Increment i by 1
- Print the "sum" variable value
Sample Solution:
C Code:
#include <stdio.h> // Include the standard input/output header file.
int main() {
int j, sum = 0; // Declare variables 'j' for the loop counter and 'sum' to store the sum.
printf("The first 10 natural numbers are :\n"); // Print a message to indicate the output.
for (j = 1; j <= 10; j++) // Start a for loop to iterate from 1 to 10.
{
sum = sum + j; // Add the current value of 'j' to the sum.
printf("%d ", j); // Print the current value of 'j'.
}
printf("\nThe Sum is : %d\n", sum); // Print the sum of the first 10 natural numbers.
return 0; // Indicate successful execution of the program.
}
Output:
The first 10 natural number is : 1 2 3 4 5 6 7 8 9 10 The Sum is : 55
Explanation:
for (j = 1; j <= 10; j++) { sum = sum + j; printf("%d ", j); }
In the above for loop, the variable j is initialized to 1, and the loop will continue as long as j is less than or equal to 10. In each iteration of the loop, the sum variable will add the value of j to itself, and the printf function will print the value of j to the console, followed by a space character.
Finally, the loop will increment the value of j by 1, and the process will repeat until the condition j <= 10 is no longer true.
Flowchart:
C Programming Code Editor:
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