C Exercises: Compute the number of seconds passed since the beginning of the month

Last update on December 20 2024 13:03:37 (UTC/GMT +8 hours)

Write a program in C to compute the number of seconds passed since the beginning of the month.

Sample Solution:

C Code:

#include <stdio.h>
#include <time.h>

int main(void) {
    time_t now; // Variable to hold the current time
    time(&now); // Get the current time

    struct tm beg_month; // Structure to hold the beginning of the month's date and time
    beg_month = *localtime(&now); // Retrieve local time
    beg_month.tm_hour = 0; // Set hours to 0
    beg_month.tm_min = 0; // Set minutes to 0
    beg_month.tm_sec = 0; // Set seconds to 0
    beg_month.tm_mday = 1; // Set day to 1 (beginning of the month)

    double seconds = difftime(now, mktime(&beg_month)); // Calculate the difference between the current time and the beginning of the month
    printf("\n %.f seconds passed since the beginning of the month.\n\n", seconds); // Print the seconds elapsed since the beginning of the month
    return 0;
}

Sample Output:

 222084 seconds passed since the beginning of the month.

N.B.: The result may varry for your current system date and time.

Flowchart:

C Programming Code Editor:

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