﻿ C : Find eligibility for admission using Nested If Statement

# C Exercises: Find eligibility for admission using Nested If Statement

## C Conditional Statement: Exercise-10 with Solution

Write a C program to find the eligibility of admission for a professional course based on the following criteria:
Marks in Maths >=65
Marks in Phy >=55
Marks in Chem>=50
Total in all three subject >=190
or
Total in Math and Physics >=140

Sample Solution:

C Code:

``````#include <stdio.h>
void main()
{  int p,c,m,t,mp;

printf("Eligibility Criteria :\n");
printf("Marks in Maths >=65\n");
printf("and Marks in Phy >=55\n");
printf("and Marks in Chem>=50\n");
printf("and Total in all three subject >=190\n");
printf("or Total in Maths and Physics >=140\n");
printf("-------------------------------------\n");

printf("Input the marks obtained in Physics :");
scanf("%d",&p);
printf("Input the marks obtained in Chemistry :");
scanf("%d",&c);
printf("Input the marks obtained in Mathematics :");
scanf("%d",&m);
printf("Total marks of Maths, Physics and Chemistry : %d\n",m+p+c);
printf("Total marks of Maths and  Physics : %d\n",m+p);

if (m>=65)
if(p>=55)
if(c>=50)
if((m+p+c)>=190||(m+p)>=140)
printf("The  candidate is eligible for admission.\n");
else
printf("The candidate is not eligible.\n");
else
printf("The candidate is not eligible.\n");
else
printf("The candidate is not eligible.\n");
else
printf("The candidate is not eligible.\n");
}
```
```

Sample Output:

```Eligibility Criteria :
Marks in Maths >=65
and Marks in Phy >=55
and Marks in Chem>=50
and Total in all three subject >=190
or Total in Maths and Physics >=140
-------------------------------------
Input the marks obtained in Physics :65
Input the marks obtained in Chemistry :51
Input the marks obtained in Mathematics :72
Total marks of Maths, Physics and Chemistry : 188
Total marks of Maths and  Physics : 137
The candidate is not eligible.
```

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## C Programming: Tips of the Day

C Programming - Execution time of C program:

CLOCKS_PER_SEC is a constant which is declared in . To get the CPU time used by a task within a C application, use:

```clock_t begin = clock();

/* here, do your time-consuming job */

clock_t end = clock();
double time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
```

Note that this returns the time as a floating point type. This can be more precise than a second (e.g. you measure 4.52 seconds). Precision depends on the architecture; on modern systems you easily get 10ms or lower, but on older Windows machines (from the Win98 era) it was closer to 60ms.

clock() is standard C; it works "everywhere". There are system-specific functions, such as getrusage() on Unix-like systems.

Ref : https://bit.ly/2NFjFb7