C Exercises: Calculate and print the average of some integers

Last update on September 18 2025 12:35:06 (UTC/GMT +8 hours)

Calculate the average of integers until 888 is entered

Write a C program to calculate and print the average of some integers. Accept all the values preceding 888.

Sample Input: 12
15
24
888

Sample Solution:

C Code:

#include <stdio.h>

int main()
{
int ctr = 0, n;       // Initialize counter and variable for input
int sum = 0;          // Initialize sum variable
float avg_value = 0;  // Initialize average variable

    // Prompt user for input
printf("Input each number on a separate line (888 to exit):\n");

    // Read the first number
scanf("%d", &n);

    // Loop until the user enters 888
while (n != 888) {
sum += n;  // Add the number to the sum
ctr++;     // Increment counter
scanf("%d", &n); // Read the next number
    }

    // Calculate the average if there were inputs
if (ctr)
avg_value = (float) sum / ctr;

    // Print the average value
printf("\nThe average value of the said numbers is %f\n", avg_value);

return 0; // Indicate successful execution of the program
}

Sample Output:

Input each number on a separate line (888 to exit):

The average value of the said numbers is 17.000000

Flowchart:

C Programming Flowchart: Calculate and print the average of some integers.

For more Practice: Solve these Related Problems:

Write a C program to compute the average of integers entered by the user, terminating when 888 is input.
Write a C program to calculate the average of positive integers until a sentinel value of 888 is encountered.
Write a C program to continuously read integers and calculate the running average until 888 is entered.
Write a C program to compute the average of user-input numbers and handle the termination condition of 888 gracefully.

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C programming Code Editor:

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