C Exercises: Display the integer equivalents of letters

C Basic Declarations and Expressions: Exercise-74 with Solution

Write a C program to display the integer equivalents of letters (a-z, A-Z).

Sample Solution:

C Code:

#include<stdio.h>
int main()
{
    // Define a string containing lowercase and uppercase letters
    char* letters = "abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    int n;

    // Print header
    printf("List of integer equivalents of letters (a-z, A-Z).\n");
    printf("==================================================\n");

    // Loop through each character and print its integer equivalent
    for(n=0; n<53; n++) {
        printf("%d\t", letters[n]);

        // Add a newline every 6 characters for better formatting
        if((n+1) % 6 == 0)
             printf("\n");
    }

    return 0;
}

Sample Output:

List of integer equivalents of letters (a-z, A-Z).
==================================================
97	98	99	100	101	102	
103	104	105	106	107	108	
109	110	111	112	113	114	
115	116	117	118	119	120	
121	122	32	65	66	67	
68	69	70	71	72	73	
74	75	76	77	78	79	
80	81	82	83	84	85	
86	87	88	89	90	

Flowchart:

C programming Code Editor:

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